Initializing an array of strings dynamically in C

Initializing an array of strings dynamically in C

I know I can initialize an array of strings this way:
static const char *BIN_ELEMENTS[5] = {
"0000\0", // 0
"0001\0", // 1
"0010\0", // 2
"0011\0", // 3
"0100\0", // 4
};
But I need to accomplish that in a dynamic way. Reading the characters
from a File, and inserting them into an array. Then copy that array into
an array of strings (like above).
So let's say I captured the following chars from a File, and inserted them
into an array, like these:
>char number[5];
>char *listOfNumbers[10];
>number[0]='1';
>number[1]='2';
>number[2]='3';
>number[3]='4';
>number[4]='\0';
Now I would like to copy the whole content of number, into listOfNumers[0]
// meaning that I've stored "1234" in position 0 of listOfNumers. Leaving
9 more positions to store different numbers.
So I would do something like this:
>listOfNumers[0] = number; //this actually seems to work.
But since its a huge file of numbers, I need to reuse the array number, to
extract a new number. But when I do that, the content previously stored in
listOfNumers[0] gets overwritten, eventho I updated the new position for
the new number. How can I deal with that?
Here is what I have so far:
char number[5]; //array for storing number>
int j=0; // counter
int c; //used to read char from file.
int k=0; // 2nd counter
char*listOfNumbers[10]; //array with all the extracted numbers.
FILE *infile;
infile = fopen("prueba.txt", "r");
if (infile)
{
` while ((c = getc(infile)) != EOF)`
` {`
` if(c != ' ' && c != '\n' && c != EOF)`
{`
` number[k] = c;`
` ++k;`
` }`
` else`
` {`
` number[k] = '\0';`
` listOfNumbers[j]=number;`
` printf("Element %d is: %s\n",j,listOfNumbers[j]); `
` ++j;`
` k=0;`
` }`
` }`
` fclose(infile);`
}
printf("\nElement 0 is: %s\n", decimales[0]); //fails - incorrect value
printf("Element 1 is: %s\n", decimales[1]); //fails - incorrect value
printf("Element 2 is: %s\n", decimales[2]); //fails - incorrect value